-36x^2+49=0

Solution for -36x^2+49=0 equation:

-36x^2+49=0

a = -36; b = 0; c = +49;
Δ = b2-4ac
Δ = 02-4·(-36)·49
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*-36}=\frac{-84}{-72}
=1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*-36}=\frac{84}{-72}
=-1+1/6
$